8+k=2k^2

Solution for 8+k=2k^2 equation:

8+k=2k^2

We move all terms to the left:

8+k-(2k^2)=0

determiningTheFunctionDomain
-2k^2+k+8=0

a = -2; b = 1; c = +8;
Δ = b2-4ac
Δ = 12-4·(-2)·8
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{65}}{2*-2}=\frac{-1-\sqrt{65}}{-4}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{65}}{2*-2}=\frac{-1+\sqrt{65}}{-4}
$